Difference between revisions of "Main Page/DAT"

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reduction in mem usage to go further up from 1.1 billion to 2.2 billion cases.
 
reduction in mem usage to go further up from 1.1 billion to 2.2 billion cases.
  
from (E=273, lx1=16, lp= 131k): limit in the past  ---> (E=546k, lx1=16, lp=131k)
+
  from (E=273, lx1=16, lp= 131k): limit in the past  ---> (E=546k, lx1=16, lp=131k)
  
 
(E=999k, lx1=16, lp=131k) was 500M. So I couldn't do on BGP. But is be ok on XK6,
 
(E=999k, lx1=16, lp=131k) was 500M. So I couldn't do on BGP. But is be ok on XK6,
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see what men usage was. From example below, always the fourth one (92352484) will
 
see what men usage was. From example below, always the fourth one (92352484) will
 
be the mem usage.
 
be the mem usage.
 
======
 
jl_sparse_cholesky.o jl_poly.o jl_tensor.o jl_findpt.o jl_pfindpt.o comm_mpi2.o rbIO_nekcem.o vtkbin.o coIO_nekcem.o coIO_nekcem_read.o io_util.o mpiio_util.o io_driver.o  -llapack -lblas
 
  text    data    bss    dec    hex filename
 
4173564  266664 87912256        92352484        5812fe4 nekcem
 
I am done
 
======
 
 
Let me know if not clear on this --
 

Revision as of 22:28, 24 March 2012

SIZEu file

 ldim: dimension
 lxi: the degree of polynomials
 lx1: the number of grid points on the face 
 ly1=lx1; lz1=lx1
 lelt: the maximun number of element per core
 lp : the maximum number of cores


We'll have to use (E,lelt,lx1,lp), to represent size of prob, instead of c3d.rea.

E=total element numbers, lelt=element # per core,
lx1= grid points in one direction, lp= # of cores.

I had many different rea with c3d_6 (E=136K), c3d_7(E=273K), etc..

Even for a fixed num of element with c3d_7 (E=273K), men usage is different for different # of cores (lp=32k, 65k, 131k). So... sorry I wouldn't know which case if it's just c3d...

By the way, please remember I made huge change in the code so far for 2 times reduction in mem usage to go further up from 1.1 billion to 2.2 billion cases.

 from (E=273, lx1=16, lp= 131k): limit in the past  ---> (E=546k, lx1=16, lp=131k)

(E=999k, lx1=16, lp=131k) was 500M. So I couldn't do on BGP. But is be ok on XK6, even with lp=262k.


If you still keep the old version old version of the code: you can compile and see what men usage was. From example below, always the fourth one (92352484) will be the mem usage.